Specific Heat Capacity (Copy)
1. Core Concept: What is Specific Heat Capacity?
- Definition: The specific heat capacity of a substance is the amount of heat energy required to raise the temperature of 1 kg of the substance by 1°C.
- Symbol:
c - Unit: J/kg°C
Formula:
Q = mcΔT
Where:
Q= energy supplied (in joules, J)m= mass of the substance (in kilograms, kg)c= specific heat capacity (J/kg°C)ΔT= temperature change (°C)
Rearranged for SHC:c = Q / (m × ΔT)
2. Objective of the Experiment
- To determine the specific heat capacity of a solid (e.g. metal block) or liquid (e.g. water) by measuring temperature change and energy input.
3. Apparatus Required
| Apparatus | Purpose |
|---|---|
| Solid metal block (aluminum, copper) or beaker with water | Test substance |
| Immersion heater (100 W or similar) | Supplies thermal energy |
| Joulemeter (or ammeter + voltmeter + stopwatch) | Measures energy input |
| Thermometer / digital temp probe | Measures temperature change |
| Digital balance | Measures mass of substance |
| Insulation (cotton, polystyrene, foil) | Minimizes heat loss |
| Lid or cork | Prevents heat loss from top |
| Stirrer (metal rod or plastic stick) | Ensures uniform temperature |
4. Step-by-Step Method: For Metal Block
- Measure mass of metal block using digital balance.
→ Record in kg - Insert immersion heater and thermometer into holes drilled in block.
- Wrap block in insulating material and cover top.
- Record initial temperature.
- Turn on power supply and start joulemeter or record V, I, and time.
- Stir occasionally to ensure even heating.
- After 5–10 minutes, record final temperature.
- Use formula:
→ If joulemeter:c = Q / (m × ΔT)
→ If not:Q = IVt, thenc = Q / (m × ΔT)
For Water (in Beaker):
Same steps as above, with:
- Use a beaker or calorimeter instead of block
- Measure mass of water only using balance
- Use stirrer to mix water evenly
5. Sample Calculation
Given:
- Mass = 1.00 kg
- Initial temp = 20°C
- Final temp = 42°C
- Energy input Q = 92400 J
Then:ΔT = 42 – 20 = 22°Cc = Q / (m × ΔT) = 92400 / (1.00 × 22) = 4200 J/kg°C
✔️ Specific heat capacity = 4200 J/kg°C
6. Data Table Example
| Time (s) | Temp (°C) |
|---|---|
| 0 | 22 |
| 60 | 25 |
| 120 | 28 |
| 180 | 31 |
| 240 | 34 |
→ Use this to plot temperature vs time and determine ΔT over total heating period.
7. Graphical Analysis
- Plot: Temperature (°C) vs Time (s)
- Use gradient if power is constant:
Slope tells you how fast temperature rises → indicates rate of energy gain
Can be used to calculate SHC indirectly
✔️ If graph is used:Q = Power × Time → estimate ΔT from graph
8. Common Errors and How to Fix Them
| Error | Correction |
|---|---|
| Heat lost to surroundings | Use insulation and lid |
| Uneven heating | Stir gently throughout |
| Inaccurate temp reading | Use digital thermometer or temperature probe |
| Incorrect mass | Measure mass without container |
| Poor electrical connections | Check circuit before timing |
| Reading V and I at wrong time | Read after steady heating starts and use average if values fluctuate |
9. Variables
| Type | Example |
|---|---|
| Independent | Time (or energy input) |
| Dependent | Temperature rise |
| Control | Mass of block, voltage, current, insulation, duration |
10. Improvement Suggestions
- Use lagging jacket or polystyrene insulation
- Cover top of beaker/block with lid or foil
- Use digital data logger for temperature recording
- Calibrate thermometer or use temp probe
- Take multiple readings and average final temperature
11. ATP-Style Questions
| Question Type | Example |
|---|---|
| Design an experiment | “Describe how you would determine the SHC of copper.” |
| Identify energy loss | “Some energy escapes into surroundings – suggest how to reduce it.” |
| Calculation | Given Q, m, ΔT → c = Q / (m × ΔT) |
| Explain improvement | “Why wrap the block in insulation?” → “To reduce heat loss to surroundings” |
| Variable control | “Why must the same mass be used?” |
| Graph interpretation | Estimate ΔT from graph to use in calculation |
12. Exam Tips
- Use Joulemeter if possible – simplest way to measure Q
- Quote
Q = mcΔTorQ = IVtbefore substitution - Convert:
→ g to kg: divide by 1000
→ minutes to seconds: ×60 - Give units and significant figures:
→ SHC usually to 2 or 3 sig figs - Label axes:
→ “Time / s”, “Temperature / °C”
Final sentence example:
“Using a joulemeter gives a total energy of 95000 J, and the temperature of the 1.2 kg metal block increased by 20°C. Therefore:
c = 95000 / (1.2 × 20) = 3958 J/kg°C ≈ 4000 J/kg°C (2 sig. figs)”
