Equation Of State (Copy)
What Is an Ideal Gas?
- An ideal gas is a theoretical model of a gas whose behavior follows a simple relationship between pressure, volume, and temperature.
- Assumes particles:
- Have negligible volume
- Experience no intermolecular forces
- Undergo perfectly elastic collisions
- Move in random motion
- Real gases behave approximately like ideal gases at:
- Low pressure
- High temperature
Basic Relationship
- For an ideal gas, the relationship between pressure (p), volume (V), and temperature (T) is:
pV ∝ T (at constant amount of gas)
- That is, pressure × volume is directly proportional to thermodynamic temperature (T in kelvin).
- This relationship becomes an equation when proportionality is replaced by constants.
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Ideal Gas Equation: pV = nRT
- The equation of state for an ideal gas is:
pV = nRT
where:
p = pressure (Pa)
V = volume (m³)
n = number of moles (mol)
R = molar gas constant = 8.314 J/mol·K
T = thermodynamic temperature (K)
Units Must Be SI:
| Quantity | Unit |
|---|---|
| Pressure (p) | pascals (Pa) = N/m² |
| Volume (V) | cubic metres (m³) |
| Temperature (T) | kelvin (K) |
| R (constant) | 8.314 J/mol·K |
Alternate Form: pV = NkT
- You can also express the ideal gas law in terms of the number of particles (N) rather than moles (n):
pV = NkT
where:
N = total number of molecules
k = Boltzmann constant = 1.38 × 10⁻²³ J/K
Relationship Between k and R
- Since n = N / Nₐ and R is the molar constant, while k is per particle:
k = R / Nₐ
where:
R = molar gas constant = 8.314 J/mol·K
Nₐ = Avogadro’s constant = 6.022 × 10²³ mol⁻¹
⇒ k = 1.38 × 10⁻²³ J/K
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Example Conversions and Usage
Example 1:
A gas has volume 0.02 m³, pressure 1.5 × 10⁵ Pa, and temperature 300 K. How many moles of gas are present?
Use pV = nRT
n = pV / RT = (1.5 × 10⁵ × 0.02) / (8.314 × 300)
n ≈ 1.20 mol
Example 2:
A container has 5.0 × 10²³ molecules of gas at 400 K in a volume of 0.01 m³. What is the pressure?
Use pV = NkT
p = NkT / V = (5.0 × 10²³ × 1.38 × 10⁻²³ × 400) / 0.01
p ≈ 2.76 × 10⁵ Pa
Ideal Gas Equation Variations
| Form | Use When |
|---|---|
| pV = nRT | When number of moles (n) is known |
| pV = NkT | When number of particles (N) is given |
| k = R / Nₐ | To switch between per mole and per particle |
Real vs Ideal Gases
| Property | Ideal Gas Assumption | Real Gas Behavior |
|---|---|---|
| Volume of particles | Negligible | Finite volume |
| Intermolecular forces | None | Attraction/repulsion present |
| Collisions | Perfectly elastic | Slight energy loss possible |
| Behavior at high pressure | Not accurate | Deviates from ideal |
- At high pressure or low temperature, real gases deviate from ideal gas law.
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Summary Table
| Equation | Description | Units |
|---|---|---|
| pV ∝ T | Basic relationship (ideal gas) | p in Pa, V in m³, T in K |
| pV = nRT | Ideal gas law using moles | R = 8.314 J/mol·K |
| pV = NkT | Ideal gas law using molecules | k = 1.38 × 10⁻²³ J/K |
| k = R / Nₐ | Definition of Boltzmann constant | Nₐ = 6.022 × 10²³ mol⁻¹ |
