Gravitational Force Between Point Masses (Copy)
Point Mass Approximation for Spheres
- For a point outside a uniform spherical object (like a planet or star), the entire mass of the object can be considered to act as if it were concentrated at a point at the centre.
- This is based on Newton’s Shell Theorem, which states:
- The gravitational effect of a spherically symmetric mass distribution on an external point is identical to that of a point mass located at the centre.
- This assumption greatly simplifies calculations involving planets, moons, and stars.
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Newton’s Law of Universal Gravitation
- The gravitational force F between two point masses m₁ and m₂, separated by distance r, is given by:
F = Gm₁m₂ / r²
where:
- F = gravitational force between the two masses (N)
- G = gravitational constant = 6.674 × 10⁻¹¹ Nm²/kg²
- m₁ and m₂ = the two masses (kg)
- r = distance between the centres of mass (m)
- The force is:
- Mutual (acts equally and oppositely on both masses)
- Attractive
- Acts along the line joining the centres of the two masses
- Inversely proportional to the square of the distance (1/r²)
- Directly proportional to the product of the two masses
Applications of Newton’s Law
- Used to calculate:
- Force between Earth and satellite
- Force between planets
- Weight of objects in orbit (gravitational force is the weight in space)
Example
Calculate the force between Earth (mass = 6.0 × 10²⁴ kg) and a 1000 kg satellite 7000 km from Earth’s centre.
F = (6.674 × 10⁻¹¹ × 6.0 × 10²⁴ × 1000) / (7.0 × 10⁶)²
F = (4.0044 × 10¹⁷) / 4.9 × 10¹³ = 8162 N
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Circular Orbits and Gravitational Force as Centripetal Force
- When a satellite or planet is in uniform circular motion around a massive body, the gravitational force acts as the centripetal force required to maintain the orbit.
- Equating the two:
F = mv² / r (centripetal force)
F = GmM / r² (gravitational force)So:
mv² / r = GmM / r²
Cancelling m and simplifying:
v² = GM / r
Taking square root:
v = √(GM / r)
- where:
- v = orbital speed
- r = orbital radius
- M = mass of the central body (e.g. Earth)
- G = gravitational constant
- where:
- This shows that:
- Orbital speed is independent of the mass of the orbiting object
- Higher central mass (M) leads to higher orbital speed
- Larger orbital radius (r) leads to slower orbital speed
Orbital Period of a Satellite
- The time T for one complete revolution (orbital period) is related to orbital radius as:
T = 2πr / v
Substitute v = √(GM / r):
T = 2πr / √(GM / r)
T = 2π√(r³ / GM)So:
T² = (4π² / GM) × r³
- This is Kepler’s Third Law: The square of the period is proportional to the cube of the radius.
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Geostationary Orbits
- A geostationary satellite is one that appears stationary above a fixed point on Earth’s surface.
- Also called geosynchronous equatorial orbit.
Key Characteristics:
- Orbital period = 24 hours (same as Earth’s rotation period)
- Direction: West to East (same as Earth’s rotation)
- Located above the equator (0° latitude)
- Orbital radius ≈ 42,000 km from Earth’s centre (approx. 35,786 km above surface)
- Remains fixed relative to one point on the Earth’s surface
Conditions for Geostationary Orbit:
- The satellite must orbit in the equatorial plane.
- The satellite must move in the direction of Earth’s rotation (west to east).
- The time period of orbit = 24 hours.
Advantages of Geostationary Satellites
- Useful for telecommunications, television broadcasting, GPS, and weather monitoring.
- Fixed position means no tracking antenna is needed on Earth.
Disadvantages
- High altitude means:
- Weak signal strength
- Long time delay (latency)
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change A2 Level Physics Full Scale Course
Summary Table
| Concept | Formula / Description |
|---|---|
| Gravitational force between point masses | F = Gm₁m₂ / r² |
| Gravitational force = centripetal force | mv² / r = GMm / r² |
| Orbital speed | v = √(GM / r) |
| Orbital period | T = 2π√(r³ / GM) |
| Conditions for geostationary orbit | Equatorial orbit, T = 24 hours, same rotation as Earth |
