Perpendicular Lines
3.7 Perpendicular Lines – Cheat Sheet
1. Key Facts About Perpendicular Lines
- If two lines are perpendicular:
m₁ × m₂ = −1 (product of gradients = −1) - Gradient of perpendicular line = negative reciprocal of the original gradient.
- Example: If m = 3, perpendicular m = −1/3
2. Finding Gradient of a Perpendicular Line
Example: Gradient of line perpendicular to 2y = 3x + 1
- Rewrite: y = (3/2)x + 1/2 → m₁ = 3/2
- Perpendicular gradient m₂ = −2/3
3. Equation of a Perpendicular Line Through a Point
Steps:
- Find gradient m₁ of given line.
- Perpendicular gradient m₂ = −1/m₁.
- Use point–slope form: y − y₁ = m₂(x − x₁).
- Rearrange to y = mx + c form.
Example: Find equation of line perpendicular to y = 4x − 1 through (2, 3)
- m₁ = 4 → m₂ = −1/4
- y − 3 = (−1/4)(x − 2)
- y − 3 = (−x/4) + 1/2
- y = (−x/4) + 7/2
4. Perpendicular Bisector of a Line Segment
Steps:
- Find midpoint of the segment: ((x₁ + x₂)/2, (y₁ + y₂)/2).
- Find gradient of segment: m₁ = (y₂ − y₁) / (x₂ − x₁).
- Perpendicular gradient m₂ = −1/m₁.
- Use midpoint and m₂ in point–slope form to get equation.
Example: Perpendicular bisector of line joining (−3, 8) and (9, −2)
- Midpoint = ((−3 + 9)/2, (8 − 2)/2) = (3, 3)
- m₁ = (−2 − 8) / (9 − (−3)) = (−10) / 12 = −5/6
- m₂ = 6/5
- Equation: y − 3 = (6/5)(x − 3)
- y = (6/5)x − 18/5 + 15/5
- y = (6/5)x − 3/5
5. Quick Reference Table
| Given Line | Gradient m₁ | Perpendicular m₂ | Equation Through (x₁, y₁) |
|---|---|---|---|
| y = 2x + 1 | 2 | −1/2 | y − y₁ = (−1/2)(x − x₁) |
| y = −3x + 4 | −3 | 1/3 | y − y₁ = (1/3)(x − x₁) |
| 4x − y = 7 | 4 | −1/4 | y − y₁ = (−1/4)(x − x₁) |
