Surface Area and Volume (Copy)
Cheat Sheet: Surface Area and Volume of Solids (IGCSE Mathematics 0580 – CORE)
Topic: Cuboid, Prism, Cylinder, Sphere, Pyramid, Cone
1. Cuboid
- Surface Area = 2(lb + bh + hl)
(l = length, b = breadth/width, h = height) - Volume = length × width × height
2. Prism (Any solid with uniform cross-section)
- Surface Area = (Perimeter of cross-section × length) + (2 × area of cross-section)
- Volume = area of cross-section × length
3. Cylinder
- Curved Surface Area = 2Ï€rh
(r = radius, h = height) - Total Surface Area = 2πrh + 2πr²
(curved area + areas of two circular ends) - Volume = πr²h
4. Sphere
- Surface Area = 4πr²
- Volume = (4/3)πr³
5. Pyramid
- Surface Area = (area of base) + (sum of areas of triangular faces)
- Volume = (1/3) × area of base × height
6. Cone
- Curved Surface Area = πrl
(r = radius, l = slant height) - Total Surface Area = πrl + πr²
(curved area + base area) - Volume = (1/3)πr²h
(h = vertical height)
7. Important Notes
- If the question asks for the answer in terms of π, leave π in the answer.
- For cones, l is the slant height and h is the vertical height.
- For prisms, cross-section must be identified first (e.g., triangle, rectangle, semicircle).
8. Quick Reference Table
| Solid | Surface Area | Volume |
|---|---|---|
| Cuboid | 2(lb + bh + hl) | l × b × h |
| Prism | Perimeter × length + 2 × cross-sectional area | Area of cross-section × length |
| Cylinder | 2πrh + 2πr² | πr²h |
| Sphere | 4πr² | (4/3)πr³ |
| Pyramid | Base area + triangular faces | (1/3) × base area × height |
| Cone | πrl + πr² | (1/3)πr²h |
This cheat sheet fully covers CORE-level formulas and methods for solving surface area and volume problems for cuboids, prisms, cylinders, spheres, pyramids, and cones.
