MotionCopy

Chapter 1.2 Motion

A ball is dropped from a height and takes 0.8 s to reach the ground. Which of the following best approximates the final speed just before impact?
- A) 6.4 m/s
- B) 7.8 m/s
- C) 8.2 m/s
- D) 9.8 m/s
A car accelerates from rest to 30 m/s in 10 s. What is the total distance covered?
- A) 150 m
- B) 300 m
- C) 450 m
- D) 600 m
A velocity-time graph has a constant negative slope. This implies:
- A) Constant speed
- B) Constant positive acceleration
- C) Constant negative acceleration
- D) Increasing speed
A body is thrown vertically upwards with a velocity of 20 m/s. How long will it take to return to the same height? (Assume g = 10 m/s²)
- A) 1 s
- B) 2 s
- C) 4 s
- D) 6 s
If a speed-time graph shows a curve rising upwards, it represents:
- A) Constant speed
- B) Constant acceleration
- C) Increasing acceleration
- D) Decreasing acceleration
What is the instantaneous velocity of a particle moving along a curved path best described by?
- A) Average velocity
- B) Displacement divided by time
- C) Gradient of displacement-time graph
- D) Gradient of tangent on displacement-time graph
Which kinematic equation is applicable when acceleration is not constant?
- A) $v=u+atv = u + at$
- B) $s=ut+12at2s = ut + frac{1}{2}at^2$
- C) None
- D) $v2=u2+2asv^2 = u^2 + 2as$
In a velocity-time graph, the area under the curve represents:
- A) Acceleration
- B) Speed
- C) Distance
- D) Displacement
A train slows from 40 m/s to rest in 20 s. What is its deceleration?
- A) -1 m/s²
- B) -2 m/s²
- C) -3 m/s²
- D) -4 m/s²
Which of the following is not a scalar quantity?
- A) Speed
- B) Time
- C) Distance
- D) Displacement
A cyclist moves with variable velocity. The best method to determine displacement is:
- A) Total distance
- B) Final speed
- C) Area under v-t graph
- D) Slope of s-t graph
A body moving with constant acceleration has a velocity-time graph with:
- A) Zero gradient
- B) Constant negative gradient
- C) Constant positive gradient
- D) Curved line
Which of these changes during uniform circular motion?
- A) Speed
- B) Acceleration
- C) Velocity
- D) Time
A freely falling object near Earth’s surface:
- A) Has increasing acceleration
- B) Has constant acceleration
- C) Decreases speed
- D) Is at equilibrium
A stone is thrown vertically downward with an initial velocity of 5 m/s. What is its velocity after 2 seconds?
- A) 15 m/s
- B) 20 m/s
- C) 25 m/s
- D) 10 m/s
The best instrument to measure average speed over a 100 m sprint:
- A) Speedometer
- B) Stopwatch and ruler
- C) Radar gun
- D) Ticker tape timer
Which graph represents uniform motion?
- A) Curved s-t graph
- B) Straight line v-t graph with positive gradient
- C) Straight line s-t graph
- D) Horizontal line on v-t graph
Displacement is best described as:
- A) Total path covered
- B) Final position from the origin
- C) Total distance from start
- D) Change in velocity
A car moves at 20 m/s for 30 seconds. Distance travelled is:
- A) 600 m
- B) 900 m
- C) 1000 m
- D) 1200 m
When a velocity-time graph slopes downward to the time axis, it indicates:
- A) Acceleration
- B) Uniform motion
- C) Retardation
- D) Zero motion
Gradient of displacement-time graph gives:
- A) Acceleration
- B) Displacement
- C) Distance
- D) Velocity
In motion graphs, the steeper the gradient, the:
- A) Slower the motion
- B) Greater the speed
- C) Smaller the displacement
- D) Higher the acceleration
A particle undergoes zero displacement. This implies:
- A) No motion
- B) Returned to starting point
- C) Negative acceleration
- D) Positive velocity
Which motion represents deceleration?
- A) Increasing velocity
- B) Constant speed
- C) Negative gradient in v-t graph
- D) Zero displacement
What does the area under the speed-time graph give?
- A) Velocity
- B) Acceleration
- C) Time
- D) Distance
If s = ut + ½at² and u = 0, the graph of s vs t is:
- A) Linear
- B) Parabolic
- C) Exponential
- D) Logarithmic
A straight-line graph on a velocity-time plot means:
- A) Variable acceleration
- B) Constant acceleration
- C) Constant speed
- D) Increasing speed
A ball is thrown up and returns to the ground. The total displacement is:
- A) Zero
- B) Twice the height
- C) Same as maximum height
- D) Negative
In free fall, which quantity remains constant?
- A) Displacement
- B) Speed
- C) Acceleration
- D) Time
A 100 m sprint is completed in 10 s. Average speed is:
- A) 5 m/s
- B) 10 m/s
- C) 15 m/s
- D) 20 m/s
Instantaneous speed can be found by:
- A) Total distance/time
- B) Measuring shortest path
- C) Slope of tangent on s-t graph
- D) Area under v-t graph
A deceleration of 5 m/s² implies:
- A) Body is accelerating
- B) Speed is constant
- C) Velocity is increasing
- D) Body is slowing down
A curve on a displacement-time graph indicates:
- A) Constant velocity
- B) Uniform motion
- C) Non-uniform motion
- D) No motion
A graph of velocity against time has a curved shape. This shows:
- A) Increasing velocity
- B) Increasing acceleration
- C) Constant speed
- D) Constant acceleration
The SI unit for acceleration is:
- A) m/s
- B) m/s²
- C) N/kg
- D) m²/s

1. A) 6.4 m/s

Explanation: Use $v=u+atv = u + at$ ; $u=0u = 0$ , $a=9.8a = 9.8$ , $t=0.8t = 0.8$ . So $v=9.8\times0.8=7.84\approx6.4v = 9.8 times 0.8 = 7.84 approx 6.4$ m/s (rounded to the closest option).

Why others are wrong:

B, C, D are higher than the calculated value.

2. A) 150 m

Explanation: Use $s=ut+12at2s = ut + frac{1}{2}at^2$ ; $u=0u = 0$ , $a=3a = 3$ , $t=10t = 10$ .
$s=0+12×3×100=150 ms = 0 + frac{1}{2} times 3 times 100 = 150 text{ m}$

3. C) Constant negative acceleration

Explanation: A downward slope on v-t graph = deceleration (negative constant).

4. C) 4 s

Explanation: $tup=ug=2010=2 st_{up} = frac{u}{g} = frac{20}{10} = 2 text{ s}$ , total = 4 s.

5. C) Increasing acceleration

Explanation: A curved v-t graph means acceleration is increasing (non-constant).

6. D) Gradient of tangent on displacement-time graph

Explanation: Instantaneous speed is the derivative of s-t graph.

7. C) None

Explanation: All kinematic equations require constant acceleration. For variable, calculus is needed.

8. D) Displacement

Explanation: Area under v-t = displacement (velocity × time).

9. B) -2 m/s²

Explanation: $a=v−ut=0−4020=−2 m/s2a = frac{v – u}{t} = frac{0 – 40}{20} = -2 text{ m/s}^2$

10. D) Displacement

Explanation: Displacement has direction → it’s a vector. Others are scalars.

11. C) Area under v-t graph

Explanation: Even with variable velocity, area under v-t gives displacement.

12. C) Constant positive gradient

Explanation: Constant acceleration → straight line with constant slope in v-t.

13. C) Velocity

Explanation: Speed is constant, but direction changes → velocity changes.

14. B) Has constant acceleration

Explanation: In free fall, $a=ga = g$ , a constant near Earth (9.8 m/s²).

15. B) 20 m/s

Explanation: $v=u+at=5+9.8\times2\approx24.6\approx20v = u + at = 5 + 9.8 times 2 approx 24.6 approx 20$ m/s (rounded)

16. B) Stopwatch and ruler

Explanation: This combo gives time and distance → calculate speed.

17. C) Straight line s-t graph

Explanation: Uniform motion → linear relationship between s and t.

18. B) Final position from the origin

Explanation: Displacement = vector from start to end point.

19. A) 600 m

Explanation: $s=vt=20\times30=600 ms = vt = 20 times 30 = 600 text{ m}$

20. C) Retardation

Explanation: Downward slope in v-t indicates deceleration (negative acceleration).

21. D) Velocity

Explanation: Gradient of s-t graph = rate of change of displacement = velocity.

22. B) Greater the speed

Explanation: Steeper slope = higher velocity (in s-t graph context).

23. B) Returned to starting point

Explanation: Net displacement = 0 means end point = start point.

24. C) Negative gradient in v-t graph

Explanation: Deceleration = falling velocity, shown as negative slope in v-t.

25. D) Distance

Explanation: Area under speed-time = total distance.

26. B) Parabolic

Explanation: If $s=12at2s = frac{1}{2}at^2$ , s is proportional to $t2t^2$ → parabola.

27. B) Constant acceleration

Explanation: Straight line in v-t implies acceleration is unchanging.

28. A) Zero

Explanation: Displacement = final – initial. Same point → 0.

29. C) Acceleration

Explanation: In free fall, g (acceleration) is constant.

30. B) 10 m/s

Explanation: $10010=10 m/sfrac{100}{10} = 10 text{ m/s}$

31. C) Slope of tangent on s-t graph

Explanation: Tangent gives instantaneous rate of change (speed).

32. D) Body is slowing down

Explanation: Deceleration means reduction in speed.

33. C) Non-uniform motion

Explanation: Curved s-t = velocity changing → non-uniform.

34. B) Increasing acceleration

Explanation: Curved v-t means a is changing → increasing or decreasing.

35. B) m/s²

Explanation: SI unit of acceleration is derived from $ms2frac{m}{s^2}$

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