Quantitative Practical Skills: Concentration Calculations Using Practical Data (Copy)
Quantitative Practical Skills
Concentration Calculations Using Practical Data
Purpose of Concentration Calculations in ATP
- Concentration calculations are used to:
- Determine the molarity of a solution from experimental data
- ATP questions test:
- Accurate use of titration data
- Correct mole calculations
- Proper unit conversions
- Clear stepwise working
- Examiners reward:
- Use of mean concordant titres
- Correct stoichiometry
- Precise significant figures
Core Examiner Rule
- Concentration formula:
Concentration (mol/dm³) = Moles of solute ÷ Volume of solution (dm³)
- Steps:
- Use mean of concordant titres
- Convert cm³ → dm³
- Calculate moles of titrant
- Apply stoichiometric ratio to find moles of analyte
- Divide moles by volume of solution in dm³
Step 1: Calculate Volume of Titrant Delivered
- Volume delivered = Final burette reading − Initial burette reading
- Use only concordant titres
- Example:
- Initial reading: 0.20 cm³
- Final reading: 23.75 cm³
- Titre: 23.55 cm³
Step 2: Convert Volume to dm³
- Conversion: Volume (dm³) = Volume (cm³) ÷ 1000
- Example: 23.55 cm³ ÷ 1000 = 0.02355 dm³
Step 3: Calculate Moles of Titrant
- Formula: Moles = Concentration × Volume (dm³)
- Example: If 0.100 mol/dm³ NaOH used:
Moles NaOH = 0.100 × 0.02355 = 0.002355 mol
Step 4: Apply Stoichiometry to Find Moles of Analyte
- Use balanced chemical equation:
HCl + Na₂CO₃ → 2 NaCl + H₂O + CO₂
- Mole ratio HCl : Na₂CO₃ = 2 : 1
- Moles Na₂CO₃ = Moles HCl ÷ 2 = 0.002355 ÷ 2 = 0.0011775 mol
Step 5: Calculate Concentration of Analyte
- Concentration (mol/dm³) = Moles ÷ Volume (dm³)
- If solution volume = 25.0 cm³ = 0.0250 dm³:
Concentration = 0.0011775 ÷ 0.0250 = 0.0471 mol/dm³
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Step 6: Converting Between Mass and Concentration (If Required)
- If question provides mass of solute, calculate moles:
Moles = Mass ÷ Relative Formula Mass (RFM)
- Then apply concentration formula:
Concentration = Moles ÷ Volume (dm³)
- Example:
Mass Na₂CO₃ = 2.64 g, RFM = 106 g/mol, Volume = 0.0500 dm³Moles = 2.64 ÷ 106 = 0.0249 mol
Concentration = 0.0249 ÷ 0.0500 = 0.498 mol/dm³
Step 7: Significant Figures and Units
- Use same significant figures as apparatus allows
- Units: mol/dm³ (not mol/L)
- Round final answer appropriately
Common Examiner Traps
- Using rough titres instead of mean concordant
- Forgetting cm³ → dm³ conversion
- Incorrect mole ratio
- Incorrect significant figures
- Units missing
High-Yield ATP Tips for Concentration Calculations
- Always start with mean concordant titre
- Convert cm³ → dm³ before calculations
- Apply stoichiometry carefully
- Show all steps clearly
- Box final answer with correct units
Core Scientific Principle
- Concentration = Measure of solute per volume of solution
- Accurate practical data and careful calculation ensure:
- Reliable results
- Maximum ATP marks
- Mastery of these calculations:
- Converts experimental data into fully creditable answers
