Quantitative Practical Skills: Percentage Yield From Experimental Data (Copy)
Quantitative Practical Skills
Percentage Yield From Experimental Data
Purpose of Percentage Yield Calculations in ATP
- Percentage yield shows:
- How much product was actually obtained compared to the theoretical maximum
- ATP questions test:
- Ability to calculate moles of reactants and products
- Correct use of stoichiometry
- Correct application of percentage yield formula
- Examiners reward:
- Stepwise method
- Clear working
- Proper units and significant figures
Core Examiner Rule
- Percentage yield formula:
Percentage yield = (Actual yield ÷ Theoretical yield) × 100
- Use:
- Mass of product for actual yield
- Calculated mass from moles for theoretical yield
- Show all steps; final answer with correct significant figures
Step 1: Identify Actual Yield
- Actual yield = mass of product obtained experimentally
- Often given in question
- Example:
- Actual yield of CuSO₄·5H₂O = 2.10 g
Step 2: Calculate Moles of Limiting Reactant
- Use balanced chemical equation
- Use formula: Moles = Mass ÷ Relative Formula Mass (RFM)
- Example: Reaction:
Cu + H₂SO₄ → CuSO₄ + H₂ - Cu used: 2.00 g
- RFM Cu = 63.5 g/mol
- Moles Cu = 2.00 ÷ 63.5 = 0.0315 mol
Step 3: Calculate Theoretical Mass of Product
- Use stoichiometry from balanced equation
- Moles of product (CuSO₄) = moles of limiting reactant = 0.0315 mol
- RFM CuSO₄·5H₂O = 249.5 g/mol
- Theoretical mass = 0.0315 × 249.5 = 7.85 g
Step 4: Calculate Percentage Yield
- Percentage yield = (Actual ÷ Theoretical) × 100
- Example:
(2.10 ÷ 7.85) × 100 = 26.8%
Written and Compiled By Sir Hunain Zia, World Record Holder With 154 Total A Grades, 7 Distinctions and 11 World Records For Educate A Change O Level And IGCSE Chemistry Full Scale Course
Step 5: Expressing the Answer Correctly
- Use correct units if required (usually % has none)
- Round to 2 significant figures unless stated otherwise
- Box the final answer
Common Examiner Traps
- Using experimental mass instead of theoretical mass in denominator
- Using wrong stoichiometric ratio
- Ignoring water of crystallisation in hydrated salts
- Using wrong RFM
- Incorrect significant figures
High-Yield ATP Tips for Percentage Yield
- Always identify the limiting reactant
- Use moles to calculate theoretical mass
- Convert all masses to grams consistently
- Apply formula carefully
- Check units and significant figures
Stepwise Example Table for Clarity
| Step | Quantity | Value |
|---|---|---|
| Actual yield | Mass product | 2.10 g |
| Limiting reactant | Moles | 0.0315 mol |
| Theoretical yield | Mass product | 7.85 g |
| Percentage yield | Actual ÷ Theoretical ×100 | 26.8% |
Core Scientific Principle
- Percentage yield measures efficiency of reaction
- Low yield can be due to:
- Side reactions
- Loss during filtration or transfer
- Incomplete reactions
- ATP marks focus on:
- Correct calculation process
- Accurate use of stoichiometry
- Presentation with proper significant figures
