Acid-Base Titrations
Understanding Acid–Base Titrations
- Definition:
An acid–base titration is a quantitative analytical method used to determine the unknown concentration of an acid or base by reacting it with a solution of known concentration until the neutralisation point (end-point) is reached. - Core Principle:
The reaction is based on the neutralisation reaction:
Acid + Base → Salt + Water
Example:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
Essential Apparatus in Acid–Base Titrations
1. Burette
- Structure:
Long, graduated glass tube with a tap at the bottom for controlled release of liquid.
Graduations typically marked in 0.1 cm³ divisions for accurate readings. - Use:
- Rinse the burette with the solution it will contain (acid or base).
- Fill using a small funnel (remove funnel before titration to avoid drips).
- Ensure no air bubbles are in the tip.
- Clamp vertically on a retort stand.
- Deliver liquid dropwise for precise control, especially near the end-point.
- Accuracy: ±0.05 cm³ when read at eye level, avoiding parallax error.
2. Volumetric Pipette
- Structure:
Narrow glass tube with a bulb in the middle, calibrated to deliver one fixed volume (commonly 25.0 cm³) with high accuracy. - Use:
- Rinse with the solution to be measured.
- Use a pipette filler for safety (never mouth pipette).
- Fill to the calibration mark, ensuring the bottom of the meniscus is level with the mark at eye level.
- Empty into the conical flask, allowing the liquid to drain naturally (do not blow out the last drop; it is accounted for in calibration).
3. Conical Flask
- Purpose:
Contains the solution from the pipette for the titration reaction. - Shape Advantage:
Narrow neck reduces splashing, wide base allows easy swirling to mix reactants.
4. Suitable Indicator
- Purpose:
Shows a visible colour change near the equivalence point (when stoichiometric amounts of acid and base have reacted). - Common Indicators for Strong Acid–Strong Base titrations:
- Phenolphthalein: Colourless in acid, pink in alkali; end-point is the first permanent pale pink colour.
- Methyl Orange: Red in acid, yellow in alkali; end-point is the first appearance of orange.
- Choice Criteria:
Indicator must change colour sharply at the equivalence point pH of the reaction.
Procedure for an Acid–Base Titration
- Preparation
- Rinse all apparatus with the correct solutions to avoid contamination or dilution.
- Burette → solution from burette (acid if acid–base titration is in this order).
- Pipette → solution to be measured (usually base in acid–base titration).
- Conical flask → distilled water (removes impurities).
- Filling the Burette
- Close tap before filling.
- Use funnel to add solution above 0.00 cm³ mark.
- Remove funnel after filling to avoid drips changing volume.
- Record initial reading to ±0.05 cm³.
- Measuring the Fixed Volume with Pipette
- Attach pipette filler, draw solution above calibration mark.
- Release until the bottom of the meniscus is exactly at the mark (eye level).
- Deliver into conical flask.
- Adding the Indicator
- Add 2–3 drops of the chosen indicator into the conical flask.
- Titration Process
- Place flask on white tile for better visibility of colour change.
- Open tap to allow solution from burette to flow into flask while swirling continuously.
- As end-point nears, slow down to dropwise addition.
- Stop at the exact moment of permanent colour change.
- Repeat for Accuracy
- Perform a rough titration to estimate the end-point.
- Perform at least two concordant titres (values within 0.10 cm³ of each other).
- Use average of concordant results for calculations.
Identifying the End-Point
- The end-point is when the indicator changes colour permanently (lasting for at least 30 seconds).
- Examples:
- With phenolphthalein:
Colourless → pale pink (stop immediately at first permanent pale pink). - With methyl orange:
Red → orange (stop as soon as orange appears).
- With phenolphthalein:
- Avoid overshooting — adding even one drop past the end-point can cause a large error in calculated concentration.
Calculations After Titration
- Formula:
c₁V₁ / n₁ = c₂V₂ / n₂
where:- c = concentration (mol/dm³)
- V = volume (dm³)
- n = mole ratio from balanced chemical equation
- Example:
If 25.0 cm³ of NaOH (c = unknown) is neutralised by 23.45 cm³ of 0.100 mol/dm³ HCl:
Reaction: HCl + NaOH → NaCl + H₂O (1:1)
Moles HCl = 0.100 × (23.45 ÷ 1000) = 2.345 × 10⁻³ mol
Moles NaOH = 2.345 × 10⁻³ mol
Concentration NaOH = (2.345 × 10⁻³) ÷ (25.0 ÷ 1000) = 0.0938 mol/dm³
