Redox, Oxidation Numbers, Displacement Reactions and Ionic Equations
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In the reaction below, which species is oxidised?
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)
A Zn
B Cu2+
C Zn2+
D Cu
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In the reaction below, which species is reduced?
Mg(s) + 2H+(aq) → Mg2+(aq) + H2(g)
A Mg
B H+
C Mg2+
D H2
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Which statement correctly describes oxidation in terms of electrons?
A gain of electrons
B loss of electrons
C gain of hydrogen
D loss of oxygen
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Which statement correctly describes reduction in terms of oxidation number?
A oxidation number increases
B oxidation number decreases
C oxidation number stays the same
D oxidation number becomes zero only
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What is the oxidation number of sulfur in H2SO4?
A –2
B +2
C +4
D +6
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What is the oxidation number of manganese in MnO4–?
A +2
B +4
C +6
D +7
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What is the oxidation number of chromium in Cr2O7 2–?
A +3
B +4
C +6
D +7
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What is the oxidation number of nitrogen in NH4+?
A –3
B –1
C +3
D +5
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Ammonium nitrate contains NH4+ and NO3– ions.
What are the oxidation numbers of nitrogen in NH4+ and NO3–?
|  | NH4+ | NO3– |
|---|---|---|
| A | –3 | +5 |
| B | +3 | –5 |
| C | –3 | –5 |
| D | +5 | –3 |
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In which substance does chlorine have oxidation number +1?
A Cl2
B HCl
C NaClO
D NaCl
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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Which change is oxidation?
A Fe3+ to Fe2+
B Cu2+ to Cu
C I– to I2
D Cl2 to Cl–
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Which change is reduction?
A Mg to Mg2+
B Fe2+ to Fe3+
C Br– to Br2
D Ag+ to Ag
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In the reaction below, which species acts as the reducing agent?
Cl2(aq) + 2Br–(aq) → 2Cl–(aq) + Br2(aq)
A Cl2
B Br–
C Cl–
D Br2
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In the reaction below, which species acts as the oxidising agent?
2Fe2+(aq) + Cl2(aq) → 2Fe3+(aq) + 2Cl–(aq)
A Fe2+
B Cl2
C Fe3+
D Cl–
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Which equation shows oxidation only?
A Cu2+ + 2e– → Cu
B Fe2+ → Fe3+ + e–
C Cl2 + 2e– → 2Cl–
D O2 + 4e– → 2O2–
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Which equation shows reduction only?
A Mg → Mg2+ + 2e–
B 2I– → I2 + 2e–
C Fe3+ + e– → Fe2+
D Zn → Zn2+ + 2e–
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Which reaction is not a redox reaction?
A Zn + CuSO4 → ZnSO4 + Cu
B 2Mg + O2 → 2MgO
C HCl + NaOH → NaCl + H2O
D Cl2 + 2KBr → 2KCl + Br2
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Which reaction involves both oxidation and reduction?
A AgNO3 + NaCl → AgCl + NaNO3
B H2SO4 + 2KOH → K2SO4 + 2H2O
C CaCO3 + 2HCl → CaCl2 + H2O + CO2
D 2Na + Cl2 → 2NaCl
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In the reaction below, what happens to iron?
Fe2O3 + 3CO → 2Fe + 3CO2
A Iron is oxidised from +3 to 0.
B Iron is reduced from +3 to 0.
C Iron is oxidised from 0 to +3.
D Iron is reduced from 0 to +3.
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In the same reaction, Fe2O3 + 3CO → 2Fe + 3CO2, what happens to carbon?
A Carbon is reduced from +2 to +4.
B Carbon is oxidised from +2 to +4.
C Carbon is reduced from +4 to +2.
D Carbon is oxidised from 0 to +4.
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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Which ionic equation correctly represents the reaction between magnesium and dilute hydrochloric acid?
A Mg(s) + 2Cl–(aq) → MgCl2(aq)
B Mg(s) + 2H+(aq) → Mg2+(aq) + H2(g)
C Mg2+(aq) + 2H+(aq) → Mg(s) + H2(g)
D Mg(s) + HCl(aq) → MgCl(aq) + H2(g)
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Which ionic equation correctly represents the reaction between copper and silver nitrate solution?
A Cu(s) + Ag+(aq) → Cu+(aq) + Ag(s)
B Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)
C Cu2+(aq) + 2Ag(s) → Cu(s) + 2Ag+(aq)
D Cu(s) + 2NO3–(aq) → Cu(NO3)2(aq)
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Which ionic equation correctly represents neutralisation?
A H+(aq) + OH–(aq) → H2O(l)
B Na+(aq) + Cl–(aq) → NaCl(aq)
C 2H+(aq) + O2–(aq) → H2O(l)
D H2(g) + O2(g) → H2O(l)
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Which ionic equation correctly represents the reaction of carbonate ions with acid?
A CO3 2–(aq) + H+(aq) → CO2(g) + OH–(aq)
B CO3 2–(aq) + 2H+(aq) → CO2(g) + H2O(l)
C CO3 2–(aq) + 2OH–(aq) → CO2(g) + H2O(l)
D CO3 2–(aq) + H2O(l) → CO2(g) + 2OH–(aq)
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Which ionic equation correctly represents the formation of silver chloride precipitate?
A Ag+(aq) + Cl–(aq) → AgCl(s)
B Ag(s) + Cl2(g) → AgCl(s)
C AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
D Ag+(aq) + NO3–(aq) → AgNO3(aq)
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Which ions are spectator ions in this reaction?
BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)
A Ba2+ and SO4 2–
B Na+ and Cl–
C Ba2+ and Cl–
D Na+ and SO4 2–
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Which ions are spectator ions in this reaction?
Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)
A Zn and Cu
B Zn2+ and Cu2+
C SO4 2– only
D Cu2+ only
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Which ionic equation represents the precipitation of lead(II) iodide?
A Pb2+(aq) + 2I–(aq) → PbI2(s)
B Pb+(aq) + I–(aq) → PbI(s)
C Pb2+(aq) + I2(aq) → PbI2(s)
D Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq)
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Which full equation has the ionic equation:
2H+(aq) + CO3 2–(aq) → CO2(g) + H2O(l)
A NaOH + HCl → NaCl + H2O
B Na2CO3 + 2HCl → 2NaCl + H2O + CO2
C AgNO3 + NaCl → AgCl + NaNO3
D Zn + 2HCl → ZnCl2 + H2
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Which full equation has the ionic equation:
Fe(s) + Cu2+(aq) → Fe2+(aq) + Cu(s)
A Fe + CuSO4 → FeSO4 + Cu
B FeCl2 + Cu → Fe + CuCl2
C Fe2O3 + 3CO → 2Fe + 3CO2
D Fe + 2HCl → FeCl2 + H2
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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A strip of zinc is placed in copper(II) sulfate solution.
Which observation is expected?
A blue solution becomes colourless and brown copper forms
B colourless solution becomes blue and copper dissolves
C green solution forms and hydrogen gas is produced
D no change occurs because zinc is less reactive than copper
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A strip of copper is placed in zinc sulfate solution.
Which observation is expected?
A zinc deposits on copper
B blue solution forms
C no reaction
D copper dissolves and zinc ions are reduced
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Which metal can displace iron from iron(II) sulfate solution?
A copper
B silver
C magnesium
D gold
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Which solution can be used to show that chlorine is more reactive than iodine?
A chlorine water added to potassium iodide solution
B iodine solution added to potassium chloride solution
C potassium chloride solution added to potassium iodide solution
D potassium iodide solution added to sodium chloride solution
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Chlorine water is added to potassium bromide solution.
Which statement is correct?
A Bromide ions are oxidised to bromine.
B Bromine is reduced to bromide ions.
C Chloride ions are oxidised to chlorine.
D Potassium ions are reduced to potassium.
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Iodine is added to potassium chloride solution.
Which observation is expected?
A purple iodine disappears and chlorine forms
B brown solution forms because iodine displaces chlorine
C no displacement reaction occurs
D potassium metal is produced
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Which halogen will displace iodine from potassium iodide solution?
A bromine only
B chlorine only
C chlorine and bromine
D iodine only
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Which halide ion is the strongest reducing agent?
A F–
B Cl–
C Br–
D I–
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Which halogen is the strongest oxidising agent?
A fluorine
B chlorine
C bromine
D iodine
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Which displacement reaction is possible?
A Cu + MgSO4 → CuSO4 + Mg
B Ag + CuSO4 → Ag2SO4 + Cu
C Fe + CuSO4 → FeSO4 + Cu
D Au + ZnSO4 → AuSO4 + Zn
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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A metal X is placed in solutions of three metal nitrates. The observations are shown.
| solution | observation |
|---|---|
| magnesium nitrate | no reaction |
| copper(II) nitrate | copper deposited |
| zinc nitrate | no reaction |
Which order of reactivity is correct?
A Mg > Zn > X > Cu
B X > Mg > Zn > Cu
C Cu > X > Zn > Mg
D Mg > X > Zn > Cu
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Metal P displaces metal Q from QSO4 solution. Metal R does not displace Q from QSO4 solution.
Which statement must be correct?
A P is more reactive than Q.
B R is more reactive than Q.
C Q is more reactive than P.
D P is less reactive than R.
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A student adds iron filings to silver nitrate solution.
Which ionic equation is most likely?
A Fe(s) + Ag+(aq) → Fe+(aq) + Ag(s)
B Fe(s) + 2Ag+(aq) → Fe2+(aq) + 2Ag(s)
C Fe2+(aq) + 2Ag(s) → Fe(s) + 2Ag+(aq)
D Ag(s) + Fe2+(aq) → Ag+(aq) + Fe(s)
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Which reaction shows hydrogen acting as a reducing agent?
A H2 + Cl2 → 2HCl
B CuO + H2 → Cu + H2O
C 2H2 + O2 → 2H2O
D H2O + CO2 → H2CO3
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Which substance is oxidised in this reaction?
CuO + H2 → Cu + H2O
A CuO
B H2
C Cu
D H2O
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Which substance is the oxidising agent in this reaction?
CuO + H2 → Cu + H2O
A CuO
B H2
C Cu
D H2O
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In the reaction below, which statement is correct?
2FeCl2 + Cl2 → 2FeCl3
A Fe2+ is oxidised to Fe3+.
B Cl2 is oxidised to Cl–.
C Fe3+ is reduced to Fe2+.
D Chloride ions are reduced to chlorine.
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Which change shows loss of oxygen?
A CuO → Cu
B Mg → MgO
C Fe2+ → Fe3+
D Cl– → Cl2
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Which change shows gain of oxygen?
A ZnO → Zn
B CO → CO2
C Fe3+ → Fe2+
D Cu2+ → Cu
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Which row is correct?
| Â | oxidising agent | reducing agent |
|---|---|---|
| A | gains electrons | loses electrons |
| B | loses electrons | gains electrons |
| C | is oxidised | is reduced |
| D | decreases another species’ oxidation number | increases another species’ oxidation number |
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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A
A right: Zn loses electrons to form Zn2+, so zinc is oxidised.
B wrong: Cu2+ gains electrons, so it is reduced.
C wrong: Zn2+ is the product of oxidation, not the species being oxidised.
D wrong: Cu is the reduced product.
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B
A wrong: Mg loses electrons, so it is oxidised.
B right: H+ gains electrons to form H2, so it is reduced.
C wrong: Mg2+ is the oxidised product.
D wrong: H2 is the reduced product, not the species being reduced.
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B
A wrong: Gain of electrons is reduction.
B right: Oxidation is loss of electrons.
C wrong: Gain of hydrogen is reduction.
D wrong: Loss of oxygen is reduction.
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B
A wrong: Oxidation number increases during oxidation.
B right: Reduction means oxidation number decreases.
C wrong: No change means no redox for that species.
D wrong: Reduction does not always make oxidation number zero.
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D
In H2SO4:
H = +1 each, total +2
O = –2 each, total –8
Overall molecule = 0
So sulfur must be +6.
A wrong: Too low.
B wrong: Too low.
C wrong: Sulfur is +4 in SO2, not H2SO4.
D right: +6.
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D
In MnO4–:
O = –2 each, total –8
Overall ion = –1
Mn + (–8) = –1
Mn = +7
A wrong: Too low.
B wrong: Too low.
C wrong: Too low by 1.
D right: +7.
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C
In Cr2O7 2–:
O = –2 each, total –14
Overall ion = –2
2Cr – 14 = –2
2Cr = +12
Cr = +6
A wrong: Too low.
B wrong: Too low.
C right: +6.
D wrong: Too high.
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A
In NH4+:
H = +1 each, total +4
Overall ion = +1
N + 4 = +1
N = –3
A right: –3.
B wrong: Too high.
C wrong: Sign is wrong.
D wrong: N is not +5 in ammonium.
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A
In NH4+: nitrogen = –3.
In NO3–: oxygen total = –6, overall charge = –1, so nitrogen = +5.
A right: –3 and +5.
B wrong: Both signs reversed.
C wrong: N in nitrate is not –5.
D wrong: Reversed.
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C
A wrong: Cl2 has chlorine oxidation number 0.
B wrong: In HCl, chlorine is –1.
C right: In NaClO, Na is +1 and O is –2, so Cl is +1.
D wrong: In NaCl, chlorine is –1.
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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C
A wrong: Fe3+ to Fe2+ is reduction because oxidation number decreases.
B wrong: Cu2+ to Cu is reduction.
C right: I– to I2 is oxidation because iodide loses electrons and oxidation number rises from –1 to 0.
D wrong: Cl2 to Cl– is reduction.
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D
A wrong: Mg to Mg2+ is oxidation.
B wrong: Fe2+ to Fe3+ is oxidation.
C wrong: Br– to Br2 is oxidation.
D right: Ag+ to Ag is reduction because silver ions gain electrons.
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B
A wrong: Cl2 is reduced, so it is the oxidising agent.
B right: Br– is oxidised to Br2, so Br– acts as the reducing agent.
C wrong: Cl– is a product.
D wrong: Br2 is the oxidised product.
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B
A wrong: Fe2+ is oxidised, so it is the reducing agent.
B right: Cl2 gains electrons and is reduced to Cl–, so Cl2 is the oxidising agent.
C wrong: Fe3+ is the oxidised product.
D wrong: Cl– is the reduced product.
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B
A wrong: Cu2+ gains electrons, so reduction.
B right: Fe2+ loses an electron to form Fe3+, so oxidation.
C wrong: Cl2 gains electrons, so reduction.
D wrong: O2 gains electrons, so reduction.
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C
A wrong: Mg loses electrons, so oxidation.
B wrong: I– loses electrons, so oxidation.
C right: Fe3+ gains an electron to form Fe2+, so reduction.
D wrong: Zn loses electrons, so oxidation.
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C
A wrong: Zinc is oxidised and copper ions are reduced.
B wrong: Magnesium is oxidised and oxygen is reduced.
C right: HCl + NaOH is neutralisation, not redox. Oxidation numbers do not change.
D wrong: Chlorine is reduced and bromide is oxidised.
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D
A wrong: This is precipitation, not redox.
B wrong: This is neutralisation, not redox.
C wrong: Acid-carbonate reaction; no oxidation number change.
D right: Sodium is oxidised and chlorine is reduced.
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B
In Fe2O3, iron is +3.
In Fe, iron is 0.
Oxidation number decreases from +3 to 0, so iron is reduced.
A wrong: Decrease is not oxidation.
B right: Iron is reduced from +3 to 0.
C wrong: Direction is reversed.
D wrong: Iron is not starting at 0.
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B
In CO, oxygen is –2, so carbon is +2.
In CO2, oxygen total is –4, so carbon is +4.
Carbon oxidation number increases from +2 to +4, so carbon is oxidised.
A wrong: Increase is not reduction.
B right: Carbon is oxidised from +2 to +4.
C wrong: Direction is reversed.
D wrong: Carbon is not 0 in CO.
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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B
A wrong: Chloride ions are spectator ions.
B right: Mg(s) + 2H+(aq) → Mg2+(aq) + H2(g).
C wrong: This shows magnesium ions becoming magnesium metal, the reverse reaction.
D wrong: HCl should be split into ions, and MgCl is not correct.
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B
A wrong: Copper normally forms Cu2+ in this reaction, not Cu+.
B right: Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s).
C wrong: This is the reverse of the actual displacement.
D wrong: Nitrate ions are spectator ions.
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A
A right: H+(aq) + OH–(aq) → H2O(l) is the ionic equation for neutralisation.
B wrong: Sodium chloride remains aqueous as ions.
C wrong: Oxide ions are not the usual neutralisation equation here.
D wrong: This is not neutralisation.
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B
A wrong: Needs 2H+ and water forms, not OH–.
B right: CO3 2–(aq) + 2H+(aq) → CO2(g) + H2O(l).
C wrong: Acid, not hydroxide, reacts with carbonate.
D wrong: Carbonate does not decompose like this in water.
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A
A right: Ag+(aq) + Cl–(aq) → AgCl(s).
B wrong: This is not the precipitation ionic equation from solution.
C wrong: This is a full equation, not ionic.
D wrong: Nitrate is spectator and silver nitrate remains soluble.
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B
Ba2+ and SO4 2– form BaSO4(s).
Na+ and Cl– remain unchanged in solution.
A wrong: These form the precipitate.
B right: Na+ and Cl– are spectator ions.
C wrong: Ba2+ is not spectator.
D wrong: SO4 2– is not spectator.
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C
Full ionic idea:
Zn(s) + Cu2+(aq) + SO4 2–(aq) → Zn2+(aq) + SO4 2–(aq) + Cu(s)
A wrong: Zn and Cu are not spectator ions; they change.
B wrong: Zn2+ is a product and Cu2+ reacts.
C right: SO4 2– is unchanged.
D wrong: Cu2+ is reduced, so it is not spectator.
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A
A right: Pb2+(aq) + 2I–(aq) → PbI2(s).
B wrong: Lead(II) is Pb2+, and PbI is wrong.
C wrong: Iodide ions, not iodine molecules, form the precipitate.
D wrong: This is the full equation, not ionic.
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B
A wrong: This gives H+ + OH– → H2O.
B right: Sodium carbonate and hydrochloric acid give carbonate + acid ionic equation.
C wrong: This gives Ag+ + Cl– → AgCl.
D wrong: This gives Zn + 2H+ → Zn2+ + H2.
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A
A right: Fe + CuSO4 → FeSO4 + Cu gives Fe + Cu2+ → Fe2+ + Cu.
B wrong: This is the reverse.
C wrong: This is reduction of iron oxide by carbon monoxide.
D wrong: This is iron reacting with acid.
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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A
A right: Zinc displaces copper from copper(II) sulfate. Blue CuSO4 solution becomes colourless ZnSO4, and brown copper forms.
B wrong: This describes copper dissolving, not zinc displacing copper.
C wrong: Hydrogen is not produced here.
D wrong: Zinc is more reactive than copper.
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C
A wrong: Copper is less reactive than zinc, so it cannot displace zinc.
B wrong: Zinc sulfate is colourless and copper does not dissolve.
C right: No reaction occurs.
D wrong: Zinc ions are not reduced by copper.
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C
A wrong: Copper is less reactive than iron.
B wrong: Silver is less reactive than iron.
C right: Magnesium is more reactive than iron and can displace it.
D wrong: Gold is much less reactive.
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A
A right: Chlorine displaces iodine from potassium iodide, showing chlorine is more reactive.
B wrong: Iodine cannot displace chlorine from potassium chloride.
C wrong: These are two halide salts, no halogen displacement.
D wrong: No displacement reaction occurs.
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A
A right: Bromide ions lose electrons and are oxidised to bromine.
B wrong: Bromide is oxidised, not bromine reduced.
C wrong: Chlorine is reduced to chloride ions.
D wrong: Potassium ions are spectators.
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C
A wrong: Iodine cannot displace chlorine from chloride solution.
B wrong: Iodine is less reactive than chlorine.
C right: No displacement reaction occurs.
D wrong: Potassium ions are spectators and are not reduced.
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C
A wrong: Bromine can displace iodine, but chlorine can too.
B wrong: Chlorine can displace iodine, but bromine can too.
C right: Chlorine and bromine are both more reactive than iodine.
D wrong: Iodine cannot displace itself meaningfully.
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D
A wrong: F– is the weakest reducing agent among halides.
B wrong: Cl– is weaker than Br– and I–.
C wrong: Br– is strong, but not the strongest here.
D right: I– is most easily oxidised, so it is the strongest reducing agent.
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A
A right: Fluorine is the strongest oxidising agent among halogens.
B wrong: Chlorine is weaker than fluorine.
C wrong: Bromine is weaker than chlorine.
D wrong: Iodine is the weakest oxidising agent listed.
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C
A wrong: Copper cannot displace magnesium.
B wrong: Silver cannot displace copper.
C right: Iron is more reactive than copper, so Fe displaces Cu from CuSO4.
D wrong: Gold cannot displace zinc.
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
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A
X does not displace Mg, so Mg is more reactive than X.
X displaces Cu, so X is more reactive than Cu.
X does not displace Zn, so Zn is more reactive than X.
Known order: Mg > Zn > X > Cu.
A right: Mg > Zn > X > Cu.
B wrong: X is not more reactive than Mg or Zn.
C wrong: Copper is not more reactive than X.
D wrong: Zinc must be above X.
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A
A right: If P displaces Q, P is more reactive than Q.
B wrong: R does not displace Q, so R is less reactive than Q.
C wrong: Q is less reactive than P.
D wrong: We cannot compare P and R directly except both relative to Q; P is above Q and R below Q, so P is likely more reactive than R, not less.
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B
A wrong: Iron usually forms Fe2+ in this displacement.
B right: Fe(s) + 2Ag+(aq) → Fe2+(aq) + 2Ag(s).
C wrong: Reverse reaction.
D wrong: Silver cannot displace iron.
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B
A wrong: Hydrogen reacts with chlorine, but this does not show hydrogen reducing a metal oxide.
B right: Hydrogen removes oxygen from CuO, reducing CuO to Cu; hydrogen acts as the reducing agent.
C wrong: Hydrogen is oxidised in combustion, but not reducing a metal oxide here.
D wrong: No redox.
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B
In CuO + H2 → Cu + H2O:
Hydrogen gains oxygen to form water, so hydrogen is oxidised.
A wrong: CuO is reduced.
B right: H2 is oxidised.
C wrong: Cu is the reduced product.
D wrong: H2O is the oxidised product.
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A
A right: CuO oxidises hydrogen to water and is itself reduced, so CuO is the oxidising agent.
B wrong: H2 is the reducing agent.
C wrong: Cu is the reduced product.
D wrong: H2O is the oxidised product.
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A
A right: Fe2+ becomes Fe3+, so iron(II) ions are oxidised.
B wrong: Cl2 is reduced to Cl–, not oxidised.
C wrong: Fe3+ is formed, not reduced.
D wrong: Chlorine is reduced to chloride ions, not the reverse.
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A
A right: CuO → Cu shows loss of oxygen, so reduction.
B wrong: Mg → MgO shows gain of oxygen.
C wrong: This is electron loss/oxidation, not oxygen loss.
D wrong: This is oxidation of chloride ions, not oxygen loss.
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B
A wrong: ZnO → Zn is loss of oxygen.
B right: CO → CO2 is gain of oxygen, so oxidation.
C wrong: Fe3+ → Fe2+ is reduction by electron gain.
D wrong: Cu2+ → Cu is reduction.
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A
A right: An oxidising agent gains electrons and causes another species to be oxidised; a reducing agent loses electrons and causes another species to be reduced.
B wrong: Reversed.
C wrong: Oxidising agents are reduced; reducing agents are oxidised.
D wrong: Oxidising agents decrease another species’ electron count by taking electrons, but the clearer correct electron-transfer row is A; this row is awkward and not the standard definition.
Written and Compiled By Sir Hunain Zia (AYLOTI), World Record Holder With 154 Total A Grades, 11 World Records and 7 Distinctions, Educate A Change.
